Q:

In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports. A student is chosen randomly from this group. What is the probability that the student plays both basketball or football?

Accepted Solution

A:
Answer: P(student plays both basketball or football)=18/25Step-by-step explanation:We are given that:In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports. Now, A student is chosen randomly from this group. What is the probability that the student plays both basketball or football?Probability of any event=no. of favorable outcomes/total no. of outcomes Β  Here, no. of favorable outcomes=no. of students who plays both basketball or football= Β 12+11-5= 18and, total no. of outcomes=25Hence, P(student plays both basketball or football)=18/25